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Microsoft Transition Your MCTS on SQL Server 2008 to MCSA: SQL Server 2012, Part 1 Sample Questions:

1. You administer a Microsoft SQL Server 2012 database. The database contains a table named Employee. Part of the Employee table is shown in the exhibit. (Click the Exhibit button.)

Confidential information about the employees is stored in a separate table named EmployeeData. One record exists within EmployeeData for each record in the Employee table. You need to assign the appropriate constraints and table properties to ensure data integrity and visibility. On which column in the Employee table should you use an identity specification to include a seed of 1,000 and an increment of 1?

A) DepartmentID
B) JobTitle
C) FirstName
D) LastName
E) EmployeeNum
F) DateHired
G) ReportsToID
H) MiddleName
I) EmployeeID

2. You have a database that contains the tables as shown in the exhibit. (Click the Exhibit button.)

You have the following query:

You need to recreate the query to meet the following requirements:
Reference columns by using one-part names only.
Sort aggregates by SalesTerritoryID, and then by ProductID.
Order the results in descending order from SalesTerritoryID to ProductID.
The solution must use the existing SELECT clause and FROM clause.
Which code segment should you use?
To answer, type the correct code in the answer area.

A) SELECT SalesTerritoryID,
ProductID,
AVG(UnitPrice),
MAX(OrderQty),
MAX(DiscountAmount)
FROM Sales.Details
ORDER BY SalesTerritoryID DESC, ProductID DESC
B) SELECT SalesTerritoryID, ProductID, AVG(UnitPrice), MAX(OrderQty), MAX(DiscountAmount) FROM Sales.Details GROUP BY SalesTerritoryID,ProductID ORDER BY SalesTerritoryID DESC, ProductID DESC

3. Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column. The business team wants a report that displays the total number of purchases made on the current day. You need to write a query that will return the correct results in the most efficient manner. Which Transact-SQL query should you use?

A) SELECT COUNT(*) FROM Purchases WHERE PurchaseTime = CONVERT(DATE, GETDATE())
B) SELECT COUNT(*) FROM Purchases WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
C) SELECT COUNT(*) FROM Purchases WHERE PurchaseTime = GETDATE()
D) SELECT COUNT(*) FROM Purchases WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))

4. You are developing a database application by using Microsoft SQL Server 2012. An application that uses a database begins to run slowly. You discover that during reads, the transaction experiences blocking from concurrent updates. You need to ensure that throughout the transaction the data maintains the original version. What should you do?

A) Enable the optimize for ad hoc workloads option.
B) Include a SET TRANSACTION ISOLATION LEVEL SERIALIZABLE statement before you run the query.
C) Include a SET TRANSACTION ISOLATION LEVEL REPEATABLE READ statement before you run the query.
D) Include a SET FORCEPLAN ON statement before you run the query.
E) Add a FORCESEEK hint to the query.
F) Add an INCLUDE clause to the index.
G) Add a LOOP hint to the query.
H) Include a SET STATISTICS PROFILE ON statement before you run the query.
I) Add a HASH hint to the query.
J) Include a SET STATISTICS SHOWPLAN_XML ON statement before you run the query.
K) Add a FORCESCAN hint to the Attach query.
L) Include a SET TRANSACTION ISOLATION LEVEL SNAPSHOT statement before you run the query.
M) Cover the unique clustered index with a columnstore index.
N) Add a columnstore index to cover the query.

5. You are a database developer for an application hosted on a Microsoft SQL Server 2012 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders. Which Transact-SQL query do you use?

A) SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
B) SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
C) SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
D) SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC

Solutions: